[Haskell-cafe] Monad fold

[Christopher Howard]

So, I'm doing something like this

foldl (>>=) someA list :: Monad m => m a

where
  list :: Monad m => [a -> m a],
  someA :: Monad m => m a

Is there a more concise way to write this? I don't think foldM is what I
want -- or is it?

-- 
frigidcode.com

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