gcd 0 0 = 0
Lars Henrik Mathiesen
17 Dec 2001 14:50:21 -0000
> From: Marc van Dongen <firstname.lastname@example.org>
> Date: Sun, 16 Dec 2001 13:35:59 +0000
> Marc van Dongen (email@example.com) wrote:
> : An integer $a$ divides integer $b$ if there exists an integer
> : $c$ such that $a c= b$.
> To make clear why $0$ (and not any other non-zero integer) is the
> gcd of $0$ and $0$ I should have added that for the integer case
> $g$ is called a greatest common divisor (gcd) of $a$ and $b$ if it
> satifies each of the following two properties:
> 1) $g$ divides both $a$ and $b$;
> 2) if $g'$ is a common divisor of $a$ and $b$ then $g'$ divides $g$.
In case it isn't clear already, these definitions make a lattice on
the positive integers, with divides ~ leq, gcd ~ meet and lcm ~ join,
using the report's definitions of gcd and lcm.
(Choosing the positive result for gcd/lcm is equivalent to noting that
divides is a partial preorder on the non-zero integers, and that the
quotient identifies x and -x).
The only thing that is lacking to make it a lattice on the
non-negative integers, is that gcd 0 0 = 0 . All other cases
involving zero (i.e., gcd 0 x = x for non-zero x, and lcm 0 x = 0
for all x) are consistent with 0 being the maximal element in the
lattice, i.e., that all integers divide zero.
Lars Mathiesen (U of Copenhagen CS Dep) <firstname.lastname@example.org> (Humour NOT marked)