Oh. Simple enough. Thanks.<br><br>Another question: why the IO in readIVar :: IVar a -> IO a, instead of just readIVar :: IVar a -> a? After all, won't readIVar iv yield the same result (eventually) every time it's called?
<br><br><div class="gmail_quote">On Dec 3, 2007 12:29 AM, Lennart Augustsson <<a href="mailto:lennart@augustsson.net">lennart@augustsson.net</a>> wrote:<br><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
You can make them from MVars.<br><br><div class="gmail_quote"><div class="Ih2E3d">On Dec 2, 2007 8:03 PM, Conal Elliott <<a href="mailto:conal@conal.net" target="_blank">conal@conal.net</a>> wrote:<br></div><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
<div class="Ih2E3d">
what became of (assign-once) IVars? afaict, they were in concurrent haskell and now aren't.<br>
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